9x^2-124x-320=0

Solution for 9x^2-124x-320=0 equation:

9x^2-124x-320=0

a = 9; b = -124; c = -320;
Δ = b2-4ac
Δ = -1242-4·9·(-320)
Δ = 26896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26896}=164$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-124)-164}{2*9}=\frac{-40}{18}
=-2+2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-124)+164}{2*9}=\frac{288}{18}
=16
$